is_resource

နမူနာ

variable တစ်ခုသည်အရင်းအမြစ်ဟုတ်မဟုတ်စစ်ဆေးပါ။

 <span class="token php language-php"><span class="token delimiter important"><? PHP</span>
<span class="token variable">$ file</span> <span class="token operator">=</span> <span class="token function">fopen</span> <span class="token punctuation">(</span> <span class="token string double-quoted-string">"test.txt"</span> <span class="token punctuation">,</span> <span class="token string double-quoted-string">"r"</span> <span class="token punctuation">)</span> <span class="token punctuation">,</span>

<span class="token keyword">လျှင်</span> <span class="token punctuation">(</span> <span class="token function">is_resource</span> <span class="token punctuation">(</span> <span class="token variable">$</span> <span class="token punctuation">ဖိုင်</span> <span class="token punctuation">)</span> <span class="token punctuation">)</span>
  <span class="token keyword">ECHO</span> <span class="token string double-quoted-string">"ဖိုင်ဖွင့်ထားသည်"</span> <span class="token punctuation">;</span>
<span class="token punctuation">}</span> <span class="token keyword">အခြား</span><span class="token punctuation">​</span>
  <span class="token keyword">echo</span> <span class="token string double-quoted-string">"Open file"</span> <span class="token punctuation">;</span>
<span class="token punctuation">}</span>
<span class="token delimiter important">></span></span>

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